CUET · MATHS · PYQ PAPER 2023
The slope of the normal to the curve \(y=x^3+3 x-2\) at its point of intersection with y-axis is:
- A 3
- B -3
- C \(\frac{1}{3}\)
- D \(-\frac{1}{3}\)
Answer & Solution
Correct Answer
(D) \(-\frac{1}{3}\)
Step-by-step Solution
Detailed explanation
Intersection with y-axis: \(x=0 \implies y = (0)^3+3(0)-2 = -2\). Point is \((0,-2)\). \(\frac{dy}{dx} = 3x^2+3\). Slope of tangent at \((0,-2)\): \(m_t = 3(0)^2+3 = 3\). Slope of normal: \(m_n = -\frac{1}{m_t} = -\frac{1}{3}\).
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