CUET · MATHS · PYQ PAPER 2023
The slope of the normal to the curve \(y^2=16 x\) at the point \((1,4)\) is :
- A \(\frac{1}{2}\)
- B \(-\frac{1}{2}\)
- C 1
- D -1
Answer & Solution
Correct Answer
(B) \(-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(2y \frac{dy}{dx} = 16\) \(\frac{dy}{dx} = \frac{16}{2y} = \frac{8}{y}\) \(m_{tangent} = \frac{8}{4} = 2\) \(m_{normal} = -\frac{1}{m_{tangent}} = -\frac{1}{2}\)
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