CUET · MATHS · PYQ PAPER 2023
The slope of tangent to the curve \(x=t^2+3 t-8, y=2 t^2-2 t-5\) at the point (2, -1) is:
- A \(\frac{22}{7}\)
- B \(-\frac{6}{7}\)
- C \(\frac{7}{6}\)
- D \(\frac{6}{7}\)
Answer & Solution
Correct Answer
(D) \(\frac{6}{7}\)
Step-by-step Solution
Detailed explanation
\( \frac{dx}{dt} = 2t + 3 \) \( \frac{dy}{dt} = 4t - 2 \) \( \frac{dy}{dx} = \frac{4t - 2}{2t + 3} \) \( t^2 + 3t - 8 = 2 \Rightarrow t^2 + 3t - 10 = 0 \Rightarrow (t-2)(t+5)=0 \Rightarrow t=2 \text{ or } t=-5 \)…
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