CUET · MATHS · PYQ PAPER 2023
The slope of tangent on the curve \(y=6 x^2-x-12\), at the point where curve meets positive \(x\)-axis is ___________ .
- A 17
- B \(-17\)
- C \(\frac{3}{2}\)
- D 19
Answer & Solution
Correct Answer
(A) 17
Step-by-step Solution
Detailed explanation
\(6x^2-x-12=0\) \(x=\frac{-(-1)\pm\sqrt{(-1)^2-4(6)(-12)}}{2(6)} = \frac{1\pm\sqrt{1+288}}{12} = \frac{1\pm\sqrt{289}}{12} = \frac{1\pm17}{12}\) \(x = \frac{1+17}{12} = \frac{18}{12} = \frac{3}{2}\) (positive x-axis) \(\frac{dy}{dx} = \frac{d}{dx}(6x^2-x-12) = 12x-1\)…
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