CUET · MATHS · PYQ PAPER 2023
The simplest form of \(\tan ^{-1}\left(\frac{\sqrt{1+x^2}-1}{x}\right), x \neq 0\) is:
- A \(\tan ^{-1} x\)
- B x
- C \(\frac{1}{2} \tan ^{-1} x\)
- D \(\sqrt{1+x^2}\)
Answer & Solution
Correct Answer
(C) \(\frac{1}{2} \tan ^{-1} x\)
Step-by-step Solution
Detailed explanation
Let \(x = \tan \theta\). \(\tan^{-1}\left(\frac{\sqrt{1+\tan^2 \theta}-1}{\tan \theta}\right)\) \(\tan^{-1}\left(\frac{\sqrt{\sec^2 \theta}-1}{\tan \theta}\right)\) \(\tan^{-1}\left(\frac{\sec \theta-1}{\tan \theta}\right)\)…
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