CUET · MATHS · PYQ PAPER 2025
The sides of an equilateral triangle are increasing at the rate of \(5 cm / sec\). The rate at which the area increases when the side is 20 cm , is
- A \(25 \sqrt{3} cm^2 / sec\)
- B \(50 \sqrt{3} cm^2 / sec\)
- C \(100 \sqrt{3} cm^2 / sec\)
- D \(15 \sqrt{3} cm^2 / sec\)
Answer & Solution
Correct Answer
(B) \(50 \sqrt{3} cm^2 / sec\)
Step-by-step Solution
Detailed explanation
\(A = \frac{\sqrt{3}}{4} s^2\) \(\frac{dA}{dt} = \frac{\sqrt{3}}{4} \cdot 2s \frac{ds}{dt} = \frac{\sqrt{3}}{2} s \frac{ds}{dt}\) \(\frac{dA}{dt} = \frac{\sqrt{3}}{2} (20) (5)\) \(\frac{dA}{dt} = 50\sqrt{3} \, cm^2 / sec\)
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