CUET · MATHS · PYQ PAPER 2023
The side of an equilateral triangle is increasing at the rate of \(3 cm / sec\).
The rate at which the area of the triangle is increasing, when the side is 4 cm , is:
- A \(6 cm^2 / sec\)
- B \(6 \sqrt{3} cm^2 / sec\)
- C \(\sqrt{3} cm^2 / sec\)
- D \(\frac{6}{\sqrt{3}} cm^2 / sec\)
Answer & Solution
Correct Answer
(B) \(6 \sqrt{3} cm^2 / sec\)
Step-by-step Solution
Detailed explanation
\(A = \frac{\sqrt{3}}{4} s^2\) \(\frac{dA}{dt} = \frac{\sqrt{3}}{2} s \frac{ds}{dt}\) \(\frac{dA}{dt} = \frac{\sqrt{3}}{2} (4) (3)\) \(\frac{dA}{dt} = 6 \sqrt{3} cm^2 / sec\)
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