CUET · MATHS · PYQ PAPER 2023
The shortest distance between the lines \(\frac{x+3}{1}=\frac{y-2}{2}=\frac{z+4}{3}\) and \(\frac{x+3}{-3}=\frac{y+7}{2}=\frac{z-6}{4}\) is :
- A \(\frac{197}{\sqrt{179}}\)
- B \(\frac{197}{\sqrt{191}}\)
- C \(\frac{197}{\sqrt{189}}\)
- D \(\frac{197}{\sqrt{237}}\)
Answer & Solution
Correct Answer
(D) \(\frac{197}{\sqrt{237}}\)
Step-by-step Solution
Detailed explanation
\(A_1=(-3, 2, -4)\), \(b_1=(1, 2, 3)\) \(A_2=(-3, -7, 6)\), \(b_2=(-3, 2, 4)\) \(A_2-A_1=(0, -9, 10)\)…
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