CUET · MATHS · PYQ PAPER 2025
The shortest distance between the lines \(\vec{r}=(\hat{i}+2 \hat{j}+3 \hat{k})+\lambda(2 \hat{i}+3 \hat{j}+4 \hat{k})\) and \(\vec{r}=(2 \hat{i}+4 \hat{j}+5 \hat{k})+\mu(4 \hat{i}+6 \hat{j}+8 \hat{k})\) is equal to
- A \(\sqrt{5}\)
- B \(\sqrt{29}\)
- C \(\sqrt{\frac{29}{5}}\)
- D \(\sqrt{\frac{5}{29}}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{\frac{5}{29}}\)
Step-by-step Solution
Detailed explanation
\(\vec{a_1} = \hat{i}+2 \hat{j}+3 \hat{k}\), \(\vec{b_1} = 2 \hat{i}+3 \hat{j}+4 \hat{k}\) \(\vec{a_2} = 2 \hat{i}+4 \hat{j}+5 \hat{k}\), \(\vec{b_2} = 4 \hat{i}+6 \hat{j}+8 \hat{k}\) Lines are parallel since \(\vec{b_2} = 2\vec{b_1}\).…
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