CUET · MATHS · PYQ PAPER 2025
The shortest distance between the lines \(\vec{r}=(\hat{i}+2 \hat{j}+3 \hat{k})+\lambda(2 \hat{i}+3 \hat{j}+4 \hat{k})\) and \(\vec{r}=(2 \hat{i}+4 \hat{j}+5 \hat{k})+\mu(3 \hat{i}+4 \hat{j}+5 \hat{k})\) is equal to :
- A \(\frac{1}{\sqrt{2}}\)
- B \(\frac{1}{\sqrt{3}}\)
- C \(\frac{1}{2}\)
- D \(\frac{1}{\sqrt{6}}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{\sqrt{6}}\)
Step-by-step Solution
Detailed explanation
\(\vec{a_2} - \vec{a_1} = (2\hat{i}+4\hat{j}+5\hat{k}) - (\hat{i}+2\hat{j}+3\hat{k}) = \hat{i}+2\hat{j}+2\hat{k}\)…
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