CUET · MATHS · PYQ PAPER 2025
The shortest distance between the lines \(\vec{r}_1=\hat{i}+\hat{j}+\lambda(2 \hat{i}-\hat{j}+\hat{k})\) and \(\vec{r}_2=2 \hat{i}+\hat{j}-\hat{k}+\mu(4 \hat{i}-2 \hat{j}+2 \hat{k})\) is :
- A \(\frac{\sqrt{66}}{6}\)
- B \(6 \sqrt{66}\)
- C \(\sqrt{66}\)
- D 6
Answer & Solution
Correct Answer
(A) \(\frac{\sqrt{66}}{6}\)
Step-by-step Solution
Detailed explanation
\(\vec{b}_1 = 2 \hat{i}-\hat{j}+\hat{k}\), \(\vec{b}_2 = 4 \hat{i}-2 \hat{j}+2 \hat{k} = 2(2 \hat{i}-\hat{j}+\hat{k}) = 2\vec{b}_1\). Lines are parallel. Let \(\vec{b} = 2 \hat{i}-\hat{j}+\hat{k}\).…
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