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CUET · MATHS · PYQ PAPER 2023

The shortest distance between the lines \(l_1\) and \(l_2\) given by
\(l_1: \vec{r}=\hat{i}+2 \hat{j}-4 \hat{k}+\lambda(2 \hat{i}+3 \hat{j}+6 \hat{k})\) and \(l_2: \vec{r}=3 \hat{i}+3 \hat{j}-5 \hat{k}+\mu(2 \hat{i}+3 \hat{j}+6 \hat{k})\) is :

  1. A \(\frac{\sqrt{290}}{7}\)
  2. B \(\frac{\sqrt{290}}{9}\)
  3. C \(\frac{\sqrt{293}}{7}\)
  4. D \(\frac{\sqrt{289}}{9}\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{\sqrt{293}}{7}\)

Step-by-step Solution

Detailed explanation

\(\vec{a_1} = \hat{i}+2 \hat{j}-4 \hat{k}\), \(\vec{a_2} = 3 \hat{i}+3 \hat{j}-5 \hat{k}\), \(\vec{b} = 2 \hat{i}+3 \hat{j}+6 \hat{k}\) \(\vec{a_2} - \vec{a_1} = (3-1)\hat{i} + (3-2)\hat{j} + (-5-(-4))\hat{k} = 2\hat{i} + \hat{j} - \hat{k}\)…
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