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CUET · MATHS · PYQ PAPER 2025

The real valued function \(f(x)=12 x^{\frac{4}{3}}-6 x^{\frac{1}{3}}, x \in[-8,8]\) has absolute maximum value equal to

  1. A \(0\)
  2. B \(-\frac{9}{4}\)
  3. C 180
  4. D 204
Verified Solution

Answer & Solution

Correct Answer

(D) 204

Step-by-step Solution

Detailed explanation

\(f'(x) = 16 x^{\frac{1}{3}} - 2 x^{-\frac{2}{3}} = 2x^{-\frac{2}{3}}(8x-1)\) Critical points: \(f'(x)=0 \Rightarrow x=\frac{1}{8}\). \(f'(x)\) undefined at \(x=0\). \(f(-8) = 12(-8)^{\frac{4}{3}}-6(-8)^{\frac{1}{3}} = 12(16)-6(-2) = 192+12 = 204\)…