CUET · MATHS · PYQ PAPER 2025
The real valued function \(f(x)=12 x^{\frac{4}{3}}-6 x^{\frac{1}{3}}, x \in[-8,8]\) has absolute maximum value equal to
- A \(0\)
- B \(-\frac{9}{4}\)
- C 180
- D 204
Answer & Solution
Correct Answer
(D) 204
Step-by-step Solution
Detailed explanation
\(f'(x) = 16 x^{\frac{1}{3}} - 2 x^{-\frac{2}{3}} = 2x^{-\frac{2}{3}}(8x-1)\) Critical points: \(f'(x)=0 \Rightarrow x=\frac{1}{8}\). \(f'(x)\) undefined at \(x=0\). \(f(-8) = 12(-8)^{\frac{4}{3}}-6(-8)^{\frac{1}{3}} = 12(16)-6(-2) = 192+12 = 204\)…
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