CUET · MATHS · PYQ PAPER 2023
The range of the function \(f(x)=\frac{1}{1-x^2}, x \neq \pm 1\) is :
- A \((-\infty,0] \cup(1, \infty)\)
- B \((-\infty, 0] \cup[1, \infty)\)
- C \((-\infty, 0) \cup(1, \infty)\)
- D \((-\infty, 0) \cup[1, \infty)\)
Answer & Solution
Correct Answer
(D) \((-\infty, 0) \cup[1, \infty)\)
Step-by-step Solution
Detailed explanation
\(y = \frac{1}{1-x^2}\) \(1-x^2 = \frac{1}{y}\) \(x^2 = 1 - \frac{1}{y}\) \(x^2 \ge 0 \implies 1 - \frac{1}{y} \ge 0\) \(\frac{y-1}{y} \ge 0\) \(y \in (-\infty, 0) \cup [1, \infty)\)
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