CUET · MATHS · PYQ PAPER 2023
"The random variable \(X\) has a probability distribution \(P ( X )\) of the following form, where \(k\) is some number.
\(P(X=x)=\left\{\begin{array}{ll}k, & \text { if } x=0 \\2 k, & \text { if } x=1 \\3 k, & \text { if } x=2 \\0, & \text { otherwise }\end{array}\right.\)
Then \(P(x \leq 2)\) is :"
- A 0
- B 1
- C \(\frac{1}{6}\)
- D \(\frac{1}{2}\)
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\(k + 2k + 3k = 1\) \(6k = 1 \Rightarrow k = \frac{1}{6}\) \(P(x \leq 2) = P(X=0) + P(X=1) + P(X=2)\) \(P(x \leq 2) = k + 2k + 3k = 6k\) \(P(x \leq 2) = 6 \left( \frac{1}{6} \right) = 1\)
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