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CUET · MATHS · PYQ PAPER 2023

The probability that a plant \(A\) survives is \(\frac{3}{4}\) and the probability that another plant \(B\) survives is \(\frac{1}{3}\).
The probability that only one of them survives is :

  1. A \(\frac{1}{6}\)
  2. B \(\frac{1}{4}\)
  3. C \(\frac{1}{12}\)
  4. D \(\frac{7}{12}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{7}{12}\)

Step-by-step Solution

Detailed explanation

\(P(\text{only one survives}) = P(A)P(B') + P(A')P(B)\) \( = \frac{3}{4} \cdot (1 - \frac{1}{3}) + (1 - \frac{3}{4}) \cdot \frac{1}{3}\) \( = \frac{3}{4} \cdot \frac{2}{3} + \frac{1}{4} \cdot \frac{1}{3}\) \( = \frac{6}{12} + \frac{1}{12}\) \( = \frac{7}{12}\)
From CUET
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