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CUET · MATHS · PYQ PAPER 2025

The probability of not getting 53 Sundays in a leap year is :

  1. A \(\frac{1}{7}\)
  2. B \(\frac{2}{7}\)
  3. C \(\frac{3}{7}\)
  4. D \(\frac{5}{7}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(\frac{5}{7}\)

Step-by-step Solution

Detailed explanation

Leap year days = \(366\) \(366 \text{ days} = 52 \text{ weeks and } 2 \text{ days}\) Possible pairs for 2 extra days = \(7\) Pairs with Sunday = \( (\text{Sun, Mon}), (\text{Sat, Sun}) \) P(53 Sundays) = \(\frac{2}{7}\) P(not 53 Sundays) = \(1 - \frac{2}{7} = \frac{5}{7}\)
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