CUET · MATHS · PYQ PAPER 2025
The probability of not getting 53 Sundays in a leap year is :
- A \(\frac{1}{7}\)
- B \(\frac{2}{7}\)
- C \(\frac{3}{7}\)
- D \(\frac{5}{7}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{7}\)
Step-by-step Solution
Detailed explanation
Leap year days = \(366\) \(366 \text{ days} = 52 \text{ weeks and } 2 \text{ days}\) Possible pairs for 2 extra days = \(7\) Pairs with Sunday = \( (\text{Sun, Mon}), (\text{Sat, Sun}) \) P(53 Sundays) = \(\frac{2}{7}\) P(not 53 Sundays) = \(1 - \frac{2}{7} = \frac{5}{7}\)
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