CUET · MATHS · PYQ PAPER 2023
The probability of a shooter hitting a target is \(\frac{2}{3}\)
Minimum how many number of times must the shooter fire so that the probability of hitting the target at least once is more than 0.98.
- A 3
- B 2
- C 4
- D 5
Answer & Solution
Correct Answer
(C) 4
Step-by-step Solution
Detailed explanation
\( 1 - \left(\frac{1}{3}\right)^n > 0.98 \) \( \left(\frac{1}{3}\right)^n \( n=3: \left(\frac{1}{3}\right)^3 = \frac{1}{27} \approx 0.037 \) \( n=4: \left(\frac{1}{3}\right)^4 = \frac{1}{81} \approx 0.0123 \) Minimum \( n = 4 \)
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