CUET · MATHS · PYQ PAPER 2025
The probability of a man hitting a target is \(\frac{1}{2}\).
How many times must he fire so that the probability of hitting the target at least once is more than \(90 \%\) ?
- A 3
- B 4
- C 5
- D 6
Answer & Solution
Correct Answer
(B) 4
Step-by-step Solution
Detailed explanation
\(P(\text{miss}) = 1 - \frac{1}{2} = \frac{1}{2}\) \(1 - \left(\frac{1}{2}\right)^n > 0.9\) \(0.1 > \left(\frac{1}{2}\right)^n\) \(2^n > 10\) \(n = 4\)
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