CUET · MATHS · PYQ PAPER 2023

The probability distribution of number of aces when two cards are drawn without replacement from a pack of 52 cards is:

A
\(x_i\) 0 1 2
\(p_i\) \(\frac{144}{221}\) \(\frac{24}{221}\) \(\frac{1}{221}\)
B
\(x_i\) 0 1 2
\(p_i\) \(\frac{144}{169}\) \(\frac{24}{144}\) \(\frac{1}{144}\)
C
\(x_i\) 0 1 2
\(p_i\) \(\frac{188}{221}\) \(\frac{32}{221}\) \(\frac{1}{221}\)
D
\(x_i\) 0 1 2
\(p_i\) \(\frac{188}{221}\) \(\frac{24}{221}\) \(\frac{1}{221}\)

Verified Solution

Answer & Solution

Correct Answer

(C)

\(x_i\)	0	1	2
\(p_i\)	\(\frac{188}{221}\)	\(\frac{32}{221}\)	\(\frac{1}{221}\)

Step-by-step Solution

Detailed explanation

Total ways to draw 2 cards: \( \binom{52}{2} = \frac{52 \times 51}{2} = 1326 \) Probability of 0 aces: \( P(X=0) = \frac{\binom{4}{0}\binom{48}{2}}{\binom{52}{2}} = \frac{1 \times 1128}{1326} = \frac{188}{221} \) Probability of 1 ace:…

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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\(x_i\)	0	1	2
\(p_i\)	\(\frac{144}{221}\)	\(\frac{24}{221}\)	\(\frac{1}{221}\)

\(x_i\)	0	1	2
\(p_i\)	\(\frac{144}{169}\)	\(\frac{24}{144}\)	\(\frac{1}{144}\)