CUET · MATHS · PYQ PAPER 2025
The probability distribution of a random variable X is
| X | 0 | 1 | 2 | 3 | 4 |
| P(X) | 0.2 | k | k | 2k | k |
Match List-I with List-II
| List-I | List-II |
| (A) value of \(k\) | (I) \(\frac{16}{25}\) |
| (B) \(P(x \geq 2)\) | (II) \(\frac{9}{25}\) |
| (C) \(P(X=3)\) | (III) \(\frac{4}{25}\) |
| (D) \(P(X<2)\) | (IV) \(\frac{8}{25}\) |
- A (A) - (III), (B) - (II), (C) - (I), (D) - (IV)
- B (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
- C (A) - (II), (B) - (III), (C) - (I), (D) - (IV)
- D (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Answer & Solution
Correct Answer
(D) (A) - (III), (B) - (I), (C) - (IV), (D) - (II)
Step-by-step Solution
Detailed explanation
(A) \(\sum P(X) = 1 \) \(0.2 + k + k + 2k + k = 1 \) \(0.2 + 5k = 1 \) \(5k = 0.8 \) \(k = 0.16 = \frac{16}{100} = \frac{4}{25} \) (A) - (III) (B) \(P(X \geq 2) = P(X=2) + P(X=3) + P(X=4) \) \(P(X \geq 2) = k + 2k + k = 4k \)…
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