CUET · MATHS · PYQ PAPER 2025
The probability distribution of a random variable X is given by
| X | 0 | 1 | 2 |
| P(X) | \(1-7 a^2\) | \(\frac{1}{2} a+\frac{1}{4}\) | \(a^2\) |
- A \(\frac{1}{16}\)
- B \(\frac{3}{18}\)
- C \(\frac{7}{16}\)
- D \(\frac{9}{16}\)
Answer & Solution
Correct Answer
(C) \(\frac{7}{16}\)
Step-by-step Solution
Detailed explanation
\( (1-7a^2) + (\frac{1}{2}a+\frac{1}{4}) + a^2 = 1 \) \( -6a^2 + \frac{1}{2}a + \frac{1}{4} = 0 \) \( 24a^2 - 2a - 1 = 0 \) \( a = \frac{2 + \sqrt{(-2)^2 - 4(24)(-1)}}{2(24)} = \frac{2 + \sqrt{4+96}}{48} = \frac{2 + 10}{48} = \frac{1}{4} \) \( P(0 \( P(0 \( P(0…
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