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CUET · MATHS · PYQ PAPER 2025

The probability distribution of a random variable X is given by
X012
P(X)k2k3k
If \(k>0\), then \(P(0 < X \leq 2)\) is equal to

  1. A \(\frac{1}{6}\)
  2. B \(\frac{5}{6}\)
  3. C \(\frac{7}{8}\)
  4. D \(\frac{9}{16}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{5}{6}\)

Step-by-step Solution

Detailed explanation

\(\sum P(X) = 1 \Rightarrow k + 2k + 3k = 1 \Rightarrow 6k = 1 \Rightarrow k = \frac{1}{6}\) \(P(0 \(P(0 < X \leq 2) = 5 \times \frac{1}{6} = \frac{5}{6}\)