CUET · MATHS · PYQ PAPER 2025
The probability distribution of a random variable \(X\) is given below :
| x | 0 | 1 | 2 | 3 |
| \(P ( x )\) | \(\frac{k}{3}\) | \(\frac{k}{2}\) | \(\frac{k}{4}\) | \(\frac{k}{7}\) |
- A \(\frac{103}{84}\)
- B \(\frac{ 8 4 }{ 1 0 3 }\)
- C \(\frac{ 8 4 }{ 1 0 2 }\)
- D \(\frac{84}{101}\)
Answer & Solution
Correct Answer
(B) \(\frac{ 8 4 }{ 1 0 3 }\)
Step-by-step Solution
Detailed explanation
\( \frac{k}{3} + \frac{k}{2} + \frac{k}{4} + \frac{k}{7} = 1 \) \( k \left( \frac{1}{3} + \frac{1}{2} + \frac{1}{4} + \frac{1}{7} \right) = 1 \) \( k \left( \frac{28+42+21+12}{84} \right) = 1 \) \( k \left( \frac{103}{84} \right) = 1 \) \( k = \frac{84}{103} \)
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