CUET · MATHS · PYQ PAPER 2023
The probability distribution of a random variable \(X\) is given under :
\(
P(X=x)=\left\{\begin{array}{ll}
k x^2 & \text { for } x=1,2,3 \\
2 k x & \text { for } x=4,5,6 \\
0 & \text { for otherwise }
\end{array}\right.
\)
Then \(P(X \geq 4)\) is :
- A \(\frac{30}{41}\)
- B \(\frac{15}{41}\)
- C \(\frac{15}{42}\)
- D \(\frac{15}{22}\)
Answer & Solution
Correct Answer
(D) \(\frac{15}{22}\)
Step-by-step Solution
Detailed explanation
\( \sum P(X=x) = 1 \) \( k(1^2) + k(2^2) + k(3^2) + 2k(4) + 2k(5) + 2k(6) = 1 \) \( k(1+4+9+8+10+12) = 1 \) \( 44k = 1 \Rightarrow k = \frac{1}{44} \) \( P(X \geq 4) = P(X=4) + P(X=5) + P(X=6) \) \( P(X \geq 4) = 2k(4) + 2k(5) + 2k(6) \) \( P(X \geq 4) = 8k + 10k + 12k = 30k \)…
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