CUET · MATHS · PYQ PAPER 2023
The points on the curve \(\frac{x^2}{9}+\frac{y^2}{16}=1\) at which the tangents are parallel to \(x\) - axis are:
- A \((0, \pm 4)\)
- B \((0,4)\)
- C \((0,-4)\)
- D \((0,0)\)
Answer & Solution
Correct Answer
(A) \((0, \pm 4)\)
Step-by-step Solution
Detailed explanation
Differentiate implicitly: \( \frac{2x}{9} + \frac{2y}{16}\frac{dy}{dx} = 0 \) Set \( \frac{dy}{dx} = 0 \): \( \frac{2x}{9} + 0 = 0 \implies x = 0 \) Substitute \( x=0 \) into the equation:…
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