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CUET · MATHS · PYQ PAPER 2023

The points on the curve \(9 y^2=x^3\) where normal to the curve makes equal intercepts with the axes is/are:

  1. A \(\left(4, \frac{8}{3}\right),\left(4, \frac{-8}{3}\right)\)
  2. B \(\left(0, \frac{8}{3}\right)\)
  3. C \(\left(0, \frac{-8}{3}\right)\)
  4. D \((4,4)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\left(4, \frac{8}{3}\right),\left(4, \frac{-8}{3}\right)\)

Step-by-step Solution

Detailed explanation

\(9 y^2=x^3\) \(18y \frac{dy}{dx} = 3x^2 \implies \frac{dy}{dx} = \frac{x^2}{6y}\) \(m_{normal} = -\frac{1}{\frac{dy}{dx}} = -\frac{6y}{x^2}\) For equal intercepts, \(m_{normal} = \pm 1\) \(-\frac{6y}{x^2} = \pm 1 \implies x^2 = \mp 6y \implies y = \mp \frac{x^2}{6}\) Substitute…
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