CUET · MATHS · PYQ PAPER 2023
The points on the curve \(9 y^2=x^3\) where normal to the curve makes equal intercepts with the axes is/are:
- A \(\left(4, \frac{8}{3}\right),\left(4, \frac{-8}{3}\right)\)
- B \(\left(0, \frac{8}{3}\right)\)
- C \(\left(0, \frac{-8}{3}\right)\)
- D \((4,4)\)
Answer & Solution
Correct Answer
(A) \(\left(4, \frac{8}{3}\right),\left(4, \frac{-8}{3}\right)\)
Step-by-step Solution
Detailed explanation
\(9 y^2=x^3\) \(18y \frac{dy}{dx} = 3x^2 \implies \frac{dy}{dx} = \frac{x^2}{6y}\) \(m_{normal} = -\frac{1}{\frac{dy}{dx}} = -\frac{6y}{x^2}\) For equal intercepts, \(m_{normal} = \pm 1\) \(-\frac{6y}{x^2} = \pm 1 \implies x^2 = \mp 6y \implies y = \mp \frac{x^2}{6}\) Substitute…
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