CUET · MATHS · PYQ PAPER 2023
The points of discontinuity of the function \(f\) defined by \(f(x)=\begin{cases} x + 2 & x \leq 1 \\x - 2 & 1 < x < 2\text { are: } \\0 & x \geq 2 \end{cases}\)
- A 0 and 1
- B 1 and 2
- C 1
- D 2
Answer & Solution
Correct Answer
(C) 1
Step-by-step Solution
Detailed explanation
At \(x=1\): \(\lim_{x \to 1^-} f(x) = 1+2 = 3\) \(\lim_{x \to 1^+} f(x) = 1-2 = -1\) Since \(\lim_{x \to 1^-} f(x) \neq \lim_{x \to 1^+} f(x)\), \(f(x)\) is discontinuous at \(x=1\). At \(x=2\): \(\lim_{x \to 2^-} f(x) = 2-2 = 0\) \(\lim_{x \to 2^+} f(x) = 0\) \(f(2) = 0\) Since…
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