CUET · MATHS · PYQ PAPER 2025
The point of local maxima of the function \(f(x)=(x-2)^5(x+2)^2\) is
- A 2
- B \(-\frac{6}{7}\)
- C \(\frac{2}{7}\)
- D -2
Answer & Solution
Correct Answer
(D) -2
Step-by-step Solution
Detailed explanation
\(f'(x) = 5(x-2)^4(x+2)^2 + 2(x-2)^5(x+2)\) \(f'(x) = (x-2)^4(x+2)[5(x+2) + 2(x-2)]\) \(f'(x) = (x-2)^4(x+2)[7x+6]\) \(f'(x) = 0 \Rightarrow x=2, x=-2, x=-\frac{6}{7}\) For \(x For \(-2 Local maxima at \(x=-2\)
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