CUET · MATHS · PYQ PAPER 2025
The particular solution of the differential equation \(x\left(1+y^2\right) d x-y\left(1+x^2\right) d y=0\), given that \(y(0)=1\) is :
- A \(x y^2=x^2+1\)
- B \(y^2=2 x^2+1\)
- C \(y^2=2 x^2+x y+1\)
- D \(x^2=3 y^2+2 x y+1\)
Answer & Solution
Correct Answer
(B) \(y^2=2 x^2+1\)
Step-by-step Solution
Detailed explanation
\(\int \frac{x}{1+x^2} d x=\int \frac{y}{1+y^2} d y\) \(\frac{1}{2} \ln \left(1+x^2\right)=\frac{1}{2} \ln \left(1+y^2\right)+C'\) \(\ln \left(1+x^2\right)=\ln \left(1+y^2\right)+C\) \(x=0, y=1 \implies \ln(1+0) = \ln(1+1)+C \implies 0 = \ln(2)+C \implies C=-\ln(2)\)…
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