CUET · MATHS · PYQ PAPER 2025
The particular solution of the differential equation \(\frac{d y}{d x}+\frac{3 y}{x}=0, y(1)=1\) is
- A \(y=\frac{1}{x^3}\)
- B \(y=\frac{1}{x^2}\)
- C \(x=\frac{1}{y}\)
- D \(x=\frac{1}{y^2}\)
Answer & Solution
Correct Answer
(A) \(y=\frac{1}{x^3}\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{y}=-\frac{3}{x} d x\) \(\int \frac{d y}{y}=\int -\frac{3}{x} d x\) \(\ln|y|=-3\ln|x|+C\) \(y=A x^{-3}\) \(1=A(1)^{-3} \Rightarrow A=1\) \(y=\frac{1}{x^3}\)
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