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CUET · MATHS · PYQ PAPER 2025

The particular solution of the differential equation \(\frac{d y}{d x}+\frac{3 y}{x}=0, y(1)=1\) is

  1. A \(y=\frac{1}{x^3}\)
  2. B \(y=\frac{1}{x^2}\)
  3. C \(x=\frac{1}{y}\)
  4. D \(x=\frac{1}{y^2}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(y=\frac{1}{x^3}\)

Step-by-step Solution

Detailed explanation

\(\frac{d y}{y}=-\frac{3}{x} d x\) \(\int \frac{d y}{y}=\int -\frac{3}{x} d x\) \(\ln|y|=-3\ln|x|+C\) \(y=A x^{-3}\) \(1=A(1)^{-3} \Rightarrow A=1\) \(y=\frac{1}{x^3}\)