CUET · MATHS · PYQ PAPER 2023
The number of solutions of the system of equations
\(\begin{array}{l}\alpha^2 x+\alpha y=-1 \\\alpha x+\alpha^2 y=1\end{array}\)
is infinite. Then \(\alpha\) is:
- A \(0\)
- B 1
- C -1
- D 2
Answer & Solution
Correct Answer
(C) -1
Step-by-step Solution
Detailed explanation
For infinite solutions: \( \frac{\alpha^2}{\alpha} = \frac{\alpha}{\alpha^2} = \frac{-1}{1} \) \( \frac{\alpha^2}{\alpha} = -1 \) \( \alpha = -1 \)
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