CUET · MATHS · PYQ PAPER 2025
The minimum value of \(Z = 3x + 2y\) subjected to the constraints \(2x + y ≥ 7, x + 2y ≥ 8 x, y ≥ 0\) is:
- A 24
- B 10
- C 12
- D 14
Answer & Solution
Correct Answer
(C) 12
Step-by-step Solution
Detailed explanation
Intersection of \(2x + y = 7\) and \(x + 2y = 8\): \(y = 7 - 2x\) \(x + 2(7 - 2x) = 8\) \(x + 14 - 4x = 8\) \(-3x = -6\) \(x = 2\) \(y = 7 - 2(2) = 3\) Corner point: \((2, 3)\) Other corner points of feasible region: \((0, 7)\) (from \(2x + y = 7\) and \(x = 0\)), \((8, 0)\)…
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