CUET · MATHS · PYQ PAPER 2025
The minimum value of the function f(x) = 3sinx - 4cosx, x ∈ [- 4π, 4π] is equal to
- A 0
- B -4
- C -5
- D -7
Answer & Solution
Correct Answer
(C) -5
Step-by-step Solution
Detailed explanation
\(R = \sqrt{a^2 + b^2}\) \(R = \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5\) Minimum value = \(-R = -5\)
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