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CUET · MATHS · PYQ PAPER 2023

The minimum value of \(f(x)=|2 x-1|\) is

  1. A \(-\infty\)
  2. B \(0\)
  3. C \(\frac{1}{2}\)
  4. D 1
Verified Solution

Answer & Solution

Correct Answer

(B) \(0\)

Step-by-step Solution

Detailed explanation

Minimum value occurs when \(2x-1=0 \Rightarrow x = \frac{1}{2}\). \(f(\frac{1}{2}) = |2(\frac{1}{2})-1| = |1-1| = 0\)
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