CUET · MATHS · PYQ PAPER 2023
The minimum value of \(f(x)=|2 x-1|\) is
- A \(-\infty\)
- B \(0\)
- C \(\frac{1}{2}\)
- D 1
Answer & Solution
Correct Answer
(B) \(0\)
Step-by-step Solution
Detailed explanation
Minimum value occurs when \(2x-1=0 \Rightarrow x = \frac{1}{2}\). \(f(\frac{1}{2}) = |2(\frac{1}{2})-1| = |1-1| = 0\)
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