CUET · MATHS · PYQ PAPER 2025
The maximum value of \(Z\) for the linear programing problem maximize \(Z=x+y\) subject to the constraints \(x+4 y \leq 8,2 x+3 y \leq 12,3 x+y \leq 9, x \geq 0, y \geq 0\) is :
- A \(3 \frac{10}{11}\)
- B \(3 \frac{9}{11}\)
- C \(4 \frac{10}{11}\)
- D \(4 \frac{9}{11}\)
Answer & Solution
Correct Answer
(A) \(3 \frac{10}{11}\)
Step-by-step Solution
Detailed explanation
\(3x+y=9 \Rightarrow y=9-3x\) \(x+4(9-3x)=8 \Rightarrow x+36-12x=8 \Rightarrow -11x=-28 \Rightarrow x=\frac{28}{11}\) \(y=9-3(\frac{28}{11}) = \frac{99-84}{11} = \frac{15}{11}\) \(Z=x+y=\frac{28}{11}+\frac{15}{11}=\frac{43}{11}\) \(\frac{43}{11} = 3 \frac{10}{11}\)
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