CUET · MATHS · PYQ PAPER 2025
The maximum value of a LPP \(z=3 x+4 y\) subject to the constraints: \(x+y \leq 6, x \geq 0, y \geq 0\) is:
- A 24
- B 30
- C 36
- D 28
Answer & Solution
Correct Answer
(A) 24
Step-by-step Solution
Detailed explanation
Vertices: \( (0,0), (6,0), (0,6) \) \( z(0,0) = 3(0)+4(0) = 0 \) \( z(6,0) = 3(6)+4(0) = 18 \) \( z(0,6) = 3(0)+4(6) = 24 \) Maximum value = \( 24 \)
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