CUET · MATHS · PYQ PAPER 2025
The largest open interval, in which the function \(f(x)=\frac{x}{x^2+1}\) increases, is
- A (0,1)
- B (-1,0)
- C (-1,1)
- D \((-\infty,-1) \cup(1, \infty)\)
Answer & Solution
Correct Answer
(C) (-1,1)
Step-by-step Solution
Detailed explanation
\(f'(x) = \frac{(1)(x^2+1) - (x)(2x)}{(x^2+1)^2} = \frac{1-x^2}{(x^2+1)^2}\) \(f'(x) > 0 \implies \frac{1-x^2}{(x^2+1)^2} > 0\) \(1-x^2 > 0 \implies x^2 \(-1 < x < 1\)
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