CUET · MATHS · PYQ PAPER 2023
The inverse of the matrix \(\left[\begin{array}{cc}2 & -1 \\ 1 & 0\end{array}\right]\) is:
- A \(\left[\begin{array}{cc}2 & -1 \\ 1 & 0\end{array}\right]\)
- B \(\left[\begin{array}{ll}-2 & 1 \\ -1 & 0\end{array}\right]\)
- C \(\left[\begin{array}{cc}2 & 1 \\ -1 & 0\end{array}\right]\)
- D \(\left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right]\)
Answer & Solution
Correct Answer
(D) \(\left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\( \det(A) = (2)(0) - (-1)(1) = 1 \) \( A^{-1} = \frac{1}{1}\left[\begin{array}{cc}0 & -(-1) \\ -1 & 2\end{array}\right] = \left[\begin{array}{cc}0 & 1 \\ -1 & 2\end{array}\right] \)
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Carboxylic acids are the earliest organic compounds isolated from nature. These are also known as organic acids but are weaker acids as compared to mineral acids. However, they are more acidic than alcohols and phenols because of greater resonance stabilization of the parent acid and its conjugate base. The acidic strength is determined by the \(K _a\), which is called the acidity constant.
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