CUET · MATHS · PYQ PAPER 2023
The inverse of the matrix \(A=\left[\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right]\) is:
- A \(\left[\begin{array}{cc}-2 & 3 \\ 1 & -2\end{array}\right]\)
- B \(\left[\begin{array}{cc}2 & -3 \\ -1 & 2\end{array}\right]\)
- C \(\left[\begin{array}{cc}-2 & -3 \\ -1 & 2\end{array}\right]\)
- D \(\left[\begin{array}{ll}2 & 3 \\ 1 & 2\end{array}\right]\)
Answer & Solution
Correct Answer
(B) \(\left[\begin{array}{cc}2 & -3 \\ -1 & 2\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(\det(A) = (2)(2) - (3)(1) = 1\) \(A^{-1} = \frac{1}{1}\left[\begin{array}{cc}2 & -3 \\ -1 & 2\end{array}\right] = \left[\begin{array}{cc}2 & -3 \\ -1 & 2\end{array}\right]\)
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