CUET · MATHS · PYQ PAPER 2023
The interval in which the function f given by \(f(x)=x^3+\frac{1}{x^3}, x \neq 0\) is increasing:
- A \((-\infty, \infty)\)
- B \((-1,0) \cup(0,1)\)
- C \((-\infty,-1) \cup(1, \infty)\)
- D \((-1,1)\)
Answer & Solution
Correct Answer
(C) \((-\infty,-1) \cup(1, \infty)\)
Step-by-step Solution
Detailed explanation
\(f'(x) = 3x^2 - 3x^{-4} = \frac{3x^6 - 3}{x^4}\) \(f'(x) > 0 \implies \frac{3x^6 - 3}{x^4} > 0\) \(3x^6 - 3 > 0 \implies x^6 > 1\) \(x 1\) \((-\infty, -1) \cup (1, \infty)\)
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