CUET · MATHS · PYQ PAPER 2023
The integral \(\int e^x\left(1+\frac{1}{x}+\log x\right) d x\) is equal to:
- A \(e^x(x+\log x)+C\)
- B \(e^x(1+\log x)+C\)
- C \(e^x \log x+C\)
- D e^x(x-\log x)+C
Answer & Solution
Correct Answer
(B) \(e^x(1+\log x)+C\)
Step-by-step Solution
Detailed explanation
\(\int e^x\left(1+\frac{1}{x}+\log x\right) d x = \int e^x\left((1+\log x) + \frac{d}{dx}(1+\log x)\right) d x\) \(= e^x(1+\log x)+C\)
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