CUET · MATHS · PYQ PAPER 2023
The integral \(\int_0^1 x(1-x)^n d x\) is equal to :
- A \(\frac{1}{(n+2)(n+3)}\)
- B \(\frac{1}{(n+1)(n+2)}\)
- C \(\frac{1}{n(n+1)}\)
- D \(\frac{1}{(n-1)(n-2)}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{(n+1)(n+2)}\)
Step-by-step Solution
Detailed explanation
\(\int_0^1 x(1-x)^n d x = \left[ -\frac{x(1-x)^{n+1}}{n+1} \right]_0^1 - \int_0^1 -\frac{(1-x)^{n+1}}{n+1} d x\) \(= 0 + \frac{1}{n+1} \left[ -\frac{(1-x)^{n+2}}{n+2} \right]_0^1\) \(= \frac{1}{n+1} \left( 0 - (-\frac{(1-0)^{n+2}}{n+2}) \right)\) \(= \frac{1}{(n+1)(n+2)}\)
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