CUET · MATHS · PYQ PAPER 2023
The general solution of the differential equation \(x\frac{d y}{d x}+2 y=x^2,x\neq 0\) is:
- A \(y=\frac{x^2}{4}+\frac{c}{x^2}\)
- B \(y=\frac{4}{x^2}+c x^2\)
- C \(y=x+\frac{c}{x^2}\)
- D \(y=x+x^2+c\)
Answer & Solution
Correct Answer
(A) \(y=\frac{x^2}{4}+\frac{c}{x^2}\)
Step-by-step Solution
Detailed explanation
Standard form: \(\frac{d y}{d x}+\frac{2}{x} y=x\) Integrating Factor \(IF=e^{\int \frac{2}{x}dx}=e^{2\ln|x|}=e^{\ln(x^2)}=x^2\) \(y \cdot x^2 = \int x \cdot x^2 dx + C\) \(y x^2 = \int x^3 dx + C\) \(y x^2 = \frac{x^4}{4} + C\) \(y = \frac{x^2}{4} + \frac{C}{x^2}\)
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