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CUET · MATHS · PYQ PAPER 2023

The general solution of the differential equation \(x d y+e^{-y} d x=x e^{x-y} d x\) is (given C is constant of integration)

  1. A \(e^x+\log x-2 x y=C\)
  2. B \(x^2+e^{-y}+x e^x=C\)
  3. C \(x e^y-y e^x+\log \left(\frac{x}{y}\right)=C\)
  4. D \(e^y-e^x+\log x=C\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(e^y-e^x+\log x=C\)

Step-by-step Solution

Detailed explanation

\(x dy = x e^{x-y} dx - e^{-y} dx\) \(x dy = e^{-y}(x e^x - 1) dx\) \(e^y dy = \left(e^x - \frac{1}{x}\right) dx\) \(\int e^y dy = \int \left(e^x - \frac{1}{x}\right) dx\) \(e^y = e^x - \log x + C\) \(e^y - e^x + \log x = C\)
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