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The general solution of the differential equation \(\log _e\left(\frac{d y}{d x}\right)=a x+b y\) is
- A \(\frac{e^{-a x}}{a}+\frac{e^{b y}}{b}+C=0\), Where \(C\) is constant of integration
- B \(\frac{e^{-a x}}{a}-\frac{e^{b y}}{b}+C=0\), Where \(C\) is constant of integration
- C \(\frac{e^{a x}}{a}+\frac{e^{-b y}}{b}+C=0\), Where \(C\) is constant of integration
- D \(\frac{e^{a x}}{a}-\frac{e^{-b y}}{b}+C=0\), Where \(C\) is constant of integration
Answer & Solution
Correct Answer
(C) \(\frac{e^{a x}}{a}+\frac{e^{-b y}}{b}+C=0\), Where \(C\) is constant of integration
Step-by-step Solution
Detailed explanation
\(\frac{d y}{d x}=e^{a x+b y}=e^{a x} e^{b y}\) \(e^{-b y} d y=e^{a x} d x\) \(\int e^{-b y} d y=\int e^{a x} d x\) \(-\frac{1}{b} e^{-b y}=\frac{1}{a} e^{a x}+C'\) \(\frac{e^{a x}}{a}+\frac{e^{-b y}}{b}+C=0\)
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