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CUET · MATHS · PYQ PAPER 2023

The general solution of the differential equation \(\frac{d y}{d x}=1+x+y+x y\) is given by:

  1. A \(\log (1+y)=x+\frac{x^2}{2}+C\), where \(C\) is a constant
  2. B \(\log y=x+\frac{x^2}{2}+C\), where \(C\) is a constant
  3. C \(\log (y-1)=x+\frac{x^2}{2}+C\), where \(C\) is a constant
  4. D \(\log (1+y)=x-\frac{x^2}{2}+C\), where \(C\) is a constant
Verified Solution

Answer & Solution

Correct Answer

(D) \(\log (1+y)=x-\frac{x^2}{2}+C\), where \(C\) is a constant

Step-by-step Solution

Detailed explanation

\(\frac{d y}{d x}=(1+x)(1+y)\) \(\int \frac{d y}{1+y}=\int (1+x) d x\) \(\log (1+y)=x+\frac{x^2}{2}+C\)