CUET · MATHS · PYQ PAPER 2023
The general solution of the differential equation \(\frac{d y}{d x}+4 x y^2=0\) is :
- A \(y=\frac{1}{2 x^2-C}\), where C is a constant
- B \(y=2 x^2-C\), where C is a constant
- C \(y=x^2-C\), where C is a constant
- D \(y=\frac{1}{x^2-C}\), where C is a constant
Answer & Solution
Correct Answer
(A) \(y=\frac{1}{2 x^2-C}\), where C is a constant
Step-by-step Solution
Detailed explanation
\(\frac{d y}{y^2}=-4x dx\) \(\int y^{-2} d y=\int -4x dx\) \(-y^{-1}=-2x^2+C'\) \(\frac{1}{y}=2x^2-C'\) \(y=\frac{1}{2x^2-C}\)
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