CUET · MATHS · PYQ PAPER 2023
The general solution of the differential equation \(\frac{d y}{d x}+\sqrt{\frac{1-y^2}{1-x^2}}=0\) is :
- A \(\sin ^{-1} x-\sin ^{-1} y=C\)
- B \(\sin ^{-1} x+\sin ^{-1} y=C\)
- C \(2 \sin ^{-1} x-\sin ^{-1} y=C\)
- D \(\log x+\log y=C\)
(Where C is Constant of integration)
Answer & Solution
Correct Answer
(B) \(\sin ^{-1} x+\sin ^{-1} y=C\)
Step-by-step Solution
Detailed explanation
\(\frac{d y}{\sqrt{1-y^2}}=-\frac{d x}{\sqrt{1-x^2}}\) \(\int \frac{d y}{\sqrt{1-y^2}}=-\int \frac{d x}{\sqrt{1-x^2}}\) \(\sin ^{-1} y=-\sin ^{-1} x+C\) \(\sin ^{-1} x+\sin ^{-1} y=C\)
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