CUET · MATHS · PYQ PAPER 2025
The general solution of the differential equation \(\frac{d y}{d x}=e^{x+y}\) is :
- A \(e^x+e^y=C\), where \(C\) is an arbitrary constant
- B \(e^x+e^{-y}=C\), where C is an arbitrary constant
- C \(e^x-e^{-y}=C\), where C is an arbitrary constant
- D \(e^x-e^y=C\), where C is an arbitrary constant
Answer & Solution
Correct Answer
(B) \(e^x+e^{-y}=C\), where C is an arbitrary constant
Step-by-step Solution
Detailed explanation
\(e^{-y} dy = e^x dx\) \(\int e^{-y} dy = \int e^x dx\) \(-e^{-y} = e^x + C'\) \(e^x + e^{-y} = -C'\) \(e^x + e^{-y} = C\)
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